NCEES · FE
FE Environmental practice questions with answers
15 free practice questions for the FE Environmental Exam (FE), spread across the exam's topics. Try each one, then open the answer to see why every option is right or wrong.
Question 1 · Mathematics
A population grows at 2% per year compounded continuously. Its doubling time is about:
- A20 years
- B50 years
- C55 years
- D35 years
Show answer and explanation
Answer: D) 35 years
For continuous exponential growth, the doubling time is ln 2 divided by the growth rate: 0.693/0.02 ≈ 35 years.
- AIncorrect. ln(1.5)/0.02 ≈ 20 years is the time for the population to grow by 50%, not to double.
- BIncorrect. 1/0.02 = 50 leaves out the ln 2 factor. For continuous growth, t = ln 2 / r.
- CIncorrect. ln 3/0.02 ≈ 55 years is the tripling time, not the doubling time.
- DCorrect. Setting N/N₀ = e^(rt) = 2 gives t = ln 2 / r = 0.693/0.02 ≈ 34.7 years.
Question 2 · Probability and Statistics
A plant has a 0.05 probability of a permit exceedance each month, independently. The probability of exceedances in both of two given months is:
- A0.0975
- B0.10
- C0.0025
- D0.05
Show answer and explanation
Answer: C) 0.0025
- AIncorrect. That's at least one.
- BIncorrect. That's adding; multiply for both.
- CCorrect. 0.05 × 0.05.
- DIncorrect. Both months must exceed.
Question 3 · Ethics and Professional Practice
A non-engineer manager orders a design change that the engineer believes is unsafe. The engineer should:
- AApprove it but not tell anyone
- BApprove it to keep the job
- CRefuse and explain the hazard
- DLet the manager seal the drawings
Show answer and explanation
Answer: C) Refuse and explain the hazard
- AIncorrect. That conceals a hazard.
- BIncorrect. Safety overrides that.
- CCorrect. Public safety comes first.
- DIncorrect. Only licensed engineers can seal.
Question 4 · Engineering Economics
An engineer deposits $1,000 at the end of each year for 5 years into an account earning 5% per year, compounded annually. Given (F/A, 5%, 5) = 5.526 and (F/P, 5%, 5) = 1.2763, the balance immediately after the fifth deposit is closest to:
- A$5,000
- B$5,526
- C$5,802
- D$6,381
Show answer and explanation
Answer: B) $5,526
For a uniform series of end-of-period deposits, the future worth is F = A(F/A, i, n) = $1,000 × 5.526 = $5,526.
- AIncorrect. This adds the five deposits and ignores the interest they earn while in the account.
- BCorrect. These are end-of-year deposits, so F = A(F/A, 5%, 5) = $1,000 × 5.526 = $5,526.
- CIncorrect. This treats the deposits as made at the start of each year (an annuity due): 5,526 × 1.05 ≈ $5,802. The deposits here are made at the end of each year.
- DIncorrect. This compounds the full $5,000 as one lump sum over 5 years (5,000 × 1.2763). Most deposits earn interest for less than 5 years, and the last earns none.
Question 5 · Fundamental Principles
In a batch test, heterotrophic bacteria consume 125 mg/L of substrate and produce 50 mg/L of new cells. What is the observed yield coefficient?
- A0.40 g cells/g substrate
- B2.5 g cells/g substrate
- C0.60 g cells/g substrate
- D0.29 g cells/g substrate
Show answer and explanation
Answer: A) 0.40 g cells/g substrate
The yield coefficient is cells produced per unit of substrate consumed: Y = 50/125 = 0.40 g cells/g substrate.
- ACorrect. Yield = mass of cells produced ÷ mass of substrate consumed = 50/125 = 0.40 g/g.
- BIncorrect. This is substrate consumed ÷ cells produced (125/50), which is the inverse of the yield.
- CIncorrect. This is (125 - 50)/125, the fraction of substrate not turned into cells. It is not the cells produced per unit of substrate.
- DIncorrect. This divides the cells by the sum of cells and substrate (50/175). Yield uses only the substrate consumed as the denominator.
Question 6 · Environmental Chemistry
The alkalinity of natural water is mainly due to:
- ANitrate
- BChloride and sulfate
- CDissolved oxygen
- DBicarbonate, carbonate and hydroxide
Show answer and explanation
Answer: D) Bicarbonate, carbonate and hydroxide
- AIncorrect. That doesn't contribute.
- BIncorrect. Those don't neutralize acid.
- CIncorrect. That isn't alkalinity.
- DCorrect. Bicarbonate usually dominates near neutral pH.
Question 7 · Health Hazards and Risk Assessment
In toxicology, chronic toxicity refers to adverse effects that result from:
- AA single exposure that produces harm immediately or within a short time
- BRepeated or long-duration exposure, often over months or years
- CA dose high enough to kill half of a group of test animals
- DA short exposure lasting a few days to a few weeks
Show answer and explanation
Answer: B) Repeated or long-duration exposure, often over months or years
Chronic toxicity comes from repeated or long-duration exposure, and its effects may appear only after a long latency period. Acute toxicity comes from a single or short-term exposure.
- AIncorrect. This describes acute toxicity: the ability of a chemical to cause harm after a single exposure.
- BCorrect. A chronically toxic substance causes damage after repeated or long-duration exposure, or causes damage that appears only after a long latency period. Carcinogens are an example.
- CIncorrect. This describes the LD50, which is a measure of acute lethality after a single dose. It is not a definition of chronic toxicity.
- DIncorrect. Exposures of days to weeks are short-term (acute or subchronic) exposures. Chronic toxicity involves long-term, repeated exposure, often for a large part of the lifetime.
Question 8 · Fluid Mechanics and Hydraulics
In the Hazen–Williams equation at a given head-loss slope, the flow capacity of a pipe is proportional to about:
- AD^0.5
- BD
- CD^2.63
- D1/D
Show answer and explanation
Answer: C) D^2.63
- AIncorrect. It grows faster than D.
- BIncorrect. It grows faster than D.
- CCorrect. Capacity rises sharply with diameter.
- DIncorrect. Larger pipes carry more.
Question 9 · Fluid Mechanics and Hydraulics
By Darcy–Weisbach, doubling a pipeline's length at the same flow changes the friction head loss by a factor of:
- A0.5
- B4
- C2
- D1
Show answer and explanation
Answer: C) 2
- AIncorrect. Longer pipe means more loss.
- BIncorrect. It's linear in L.
- CCorrect. Head loss is proportional to L.
- DIncorrect. Loss depends on length.
Question 10 · Surface Water Resources and Hydrology
A lake holds 1 × 10⁸ m³ and has an outflow of 1 × 10⁶ m³/day. Its hydraulic residence time is:
- A100 days
- B0.01 days
- C10 days
- D1,000 days
Show answer and explanation
Answer: A) 100 days
- ACorrect. τ = V/Q = 10⁸/10⁶ days.
- BIncorrect. That's inverted.
- CIncorrect. Recheck the powers of ten.
- DIncorrect. Recheck the powers of ten.
Question 11 · Groundwater, Soils, and Sediments
An organic contaminant with a high organic-carbon partition coefficient (Koc) tends to:
- ASorb strongly to soil and move slowly
- BMove with the groundwater unretarded
- CEvaporate completely
- DDissolve completely in water
Show answer and explanation
Answer: A) Sorb strongly to soil and move slowly
- ACorrect. Its retardation factor is high.
- BIncorrect. It sorbs strongly.
- CIncorrect. Koc describes sorption.
- DIncorrect. It prefers organic carbon.
Question 12 · Water and Wastewater
A clarifier with 50 m² of surface area receives 2,000 m³/day. The surface overflow rate is:
- A40 m³/(m²·day)
- B0.025 m³/(m²·day)
- C100,000 m³/(m²·day)
- D4 m³/(m²·day)
Show answer and explanation
Answer: A) 40 m³/(m²·day)
- ACorrect. Q/A = 2,000/50.
- BIncorrect. That's inverted.
- CIncorrect. Divide, don't multiply.
- DIncorrect. Recheck: 2,000/50.
Question 13 · Water and Wastewater
Nitrification affects alkalinity by:
- AHaving no effect
- BAdding a large amount of alkalinity
- CConsuming alkalinity
- DRaising pH sharply
Show answer and explanation
Answer: C) Consuming alkalinity
- AIncorrect. It consumes alkalinity.
- BIncorrect. Denitrification recovers some.
- CCorrect. It uses about 7.1 mg as CaCO₃ per mg of ammonia-N; low alkalinity can stall nitrification.
- DIncorrect. It lowers pH.
Question 14 · Air Quality and Control
Which statement best describes how ground-level (tropospheric) ozone forms in urban air?
- AVehicle engines and industrial boilers emit ozone directly in their exhaust
- BNitrogen oxides and volatile organic compounds react photochemically in sunlight
- CChlorine released when chlorofluorocarbons break down in ultraviolet light combines with oxygen
- DSulfur dioxide oxidizes in cloud droplets and releases ozone as a by-product
Show answer and explanation
Answer: B) Nitrogen oxides and volatile organic compounds react photochemically in sunlight
Ground-level ozone is a secondary pollutant. It forms when NOx and VOCs, mostly from burning fossil fuels, react in sunlight.
- AIncorrect. Ground-level ozone is a secondary pollutant. Combustion sources emit its precursors, mainly NOx and VOCs, not ozone itself.
- BCorrect. Ozone forms when NOx and VOCs react in sunlight, so levels peak on hot, sunny afternoons downwind of traffic and industry.
- CIncorrect. Chlorine from CFCs destroys ozone in the stratosphere. It does not form ozone at ground level.
- DIncorrect. Sulfur dioxide oxidizing in droplets forms sulfate, which causes acid rain and fine particles. It is not an ozone formation pathway.
Question 15 · Solid and Hazardous Waste
In a landfill, the leachate collection layer is placed:
- ADirectly above the liner
- BBeneath the liner
- COn top of the final cover
- DInside the waste only at the surface
Show answer and explanation
Answer: A) Directly above the liner
- ACorrect. It drains leachate to sumps before it builds head on the liner.
- BIncorrect. That would let leachate reach the liner first.
- CIncorrect. That's for stormwater.
- DIncorrect. It sits at the base.
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